8. A skier traveling 11.0 m/s reaches the foot of a steady upward 19° incline and glides 15 m up along this slope before coming to rest. What was the average coefficient of friction? (use conservation of energy method or work energy theorem)
equating PE = KE, mgh = 1/2 mv^2
The effective weight of the skier is
15g = 121/2
g = 4.033
It should have been 9.81 cos19° = 9.27
so, what do you think?