If a given mass of a gas at 28c occupies a volume of 76cm3 what is the volume in cm3 of the gas at stp when the pressure is constant
Use (V1/T1) = (V2/T2)
Don't for get to convert T in degrees C to T in degrees kelvin.
Oh, hello there! It seems like you need some help with a gas-related question. Don't worry, I've got just the right amount of humor and knowledge to assist you!
Now, let's tackle this problem. At STP (Standard Temperature and Pressure), the temperature is 0°C (or 273K) and the pressure is 1 atm. To find the volume at STP, we can use the combined gas law:
(P1 * V1) / T1 = (P2 * V2) / T2
Since the pressure is constant, we can simplify the equation to:
V1 / T1 = V2 / T2
Alright, let's plug in the given values! We have V1 = 76 cm³ and T1 = 28°C (we need to convert this to Kelvin by adding 273).
(76 cm³) / (273 + 28°C) = V2 / 273K
Okay, time for some calculations.
(76 cm³) / 301K ≈ 0.253 cm³/K * (273 K) ≈ 69 cm³
Therefore, the volume of the gas at STP, with constant pressure, is approximately 69 cm³.
I hope my amusing explanation made this problem a little less gas-tly! Feel free to let me know if you need any further assistance.
To find the volume of the gas at STP (Standard Temperature and Pressure), we need to assume that the pressure is constant. At STP, the temperature is 0°C or 273K, and the pressure is 1 atmosphere (atm).
Given:
Initial temperature (T1) = 28°C
Initial volume (V1) = 76 cm^3
To calculate the final volume (V2) at STP, we can use the ideal gas law equation:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = Initial pressure
P2 = Final pressure (considering it is constant)
T1 = Initial temperature
T2 = Final temperature (STP temperature)
V1 = Initial volume
V2 = Final volume (what we need to find)
Since the pressure is constant, we can simplify the equation to:
(V1 / T1) = (V2 / T2)
Rearranging the terms, we get:
V2 = (V1 * T2) / T1
Substituting the values:
V2 = (76 cm^3 * 273 K) / (28°C + 273)
Converting the Celsius temperature to Kelvin:
V2 = (76 cm^3 * 273 K) / 301 K
Calculating:
V2 ≈ 69.20 cm^3
Therefore, the volume of the gas at STP, assuming the pressure is constant, is approximately 69.20 cm^3.
To find the volume of the gas at STP (Standard Temperature and Pressure), we need to use the ideal gas law. The ideal gas law is given by the equation:
PV = nRT
Where:
P = Pressure of the gas
V = Volume of the gas
n = Number of moles of the gas
R = Ideal gas constant
T = Temperature of the gas
At STP, the temperature is 0°C or 273.15K, and the pressure is 1 atmosphere (atm).
Given:
Temperature (T1) = 28°C
Volume (V1) = 76 cm^3
First, we need to convert the temperature from Celsius to Kelvin:
T1 = 28°C + 273.15 = 301.15K
Assuming the pressure is constant, we can rewrite the ideal gas law equation as:
V1/T1 = V2/T2
Solving for V2 (the volume at STP):
V2 = V1 * (T2 / T1)
Substituting the values:
V2 = 76 cm^3 * (273.15K / 301.15K)
Calculating the volume at STP:
V2 = 69.1 cm^3 (approximately)
Therefore, the volume of the gas at STP, when the pressure is constant, is approximately 69.1 cm^3.