A heater marked 60N euaporates 6×10kg of boiling water in seconds. What is the specific latent heat of vaporization of water in J/kg?
N??? Newtons ??? what ???
in ??? seconds ???
60 kg or what???
Please proof read ! I do not read minds remotely.
You did not answer my qustion.
Why are you telling me to ask question, when you have not answer my question, seriously .
To find the specific latent heat of vaporization of water, we need to divide the energy supplied by the heater (in joules) by the mass of water evaporated (in kilograms).
In this case, we are given that the heater marked 60N (Newtons) evaporates 6×10kg of boiling water in seconds. Let's convert the force from Newtons to joules:
1 Newton (N) = 1 Joule (J)
Therefore, 60N = 60J
Now, we can calculate the specific latent heat of vaporization of water using the formula:
Specific Latent Heat = Energy / Mass
Given:
Energy supplied by the heater (E) = 60J
Mass of water evaporated (m) = 6×10kg
Specific Latent Heat = 60J / (6×10kg)
Specific Latent Heat = 10 J/kg
Therefore, the specific latent heat of vaporization of water is 10 J/kg.