A spiral spring of natural length 20.00cm has a scalepan hanging freely at a lower rate.When an object of mass 40g is placed in the ground,it lengths become 21.8cm.When another object of mass 60g is placed in the ground it lengths become 22.05cm.Calculate the mass of the scale pan taken g as 10m/s
(s + 40 g) * k = (21.8 - 20) cm = 1.8 cm
(s + 60 g) * k = (22.05 - 20) cm = 2.05 cm
subtracting equations ... 20 g * k = .25 cm ... k = .0125 cm/g
substituting ... (s + 40 g) * .0125 cm/g = 1.8 cm
solve for s