Two forces f1 and f2 act on a particle.F1 has a magnitude and and in direction 030,and f2 has magnitude 8N and in direction 090.Find the direction of their resultant?
To find the direction of the resultant force, we can use vector addition.
1. Start by drawing a coordinate plane with the given directions. The direction 030 means the angle is measured from the positive x-axis in the counterclockwise direction. The direction 090 means the angle is measured from the positive x-axis in the counterclockwise direction.
2. Draw the vectors f1 and f2 on the coordinate plane. The vector f1 has a magnitude (size) and it is directed at an angle of 30 degrees counterclockwise from the positive x-axis. The vector f2 has a magnitude (size) of 8 N and it is directed at an angle of 90 degrees counterclockwise from the positive x-axis.
3. Starting at the origin of the coordinate plane, draw vector f1 according to its magnitude and direction. Then, draw vector f2 according to its magnitude and direction, starting from the endpoint of f1.
4. To find the resultant force, we need to add these vectors together. To do this, draw a vector from the origin to the endpoint of the second vector (f2). This vector represents the resultant force.
5. The direction of the resultant force can be measured counterclockwise from the positive x-axis. To find this direction, you can use the tangent function. The tangent of the angle can be calculated by dividing the y-component of the resultant force by the x-component of the resultant force.
6. Calculate the tangent of the angle by dividing the y-component of the resultant force by the x-component of the resultant force.
7. Once you have calculated the tangent of the angle, use the inverse tangent function (tan^-1) to find the angle itself.
8. The angle you find will be the direction of the resultant force.