9.0g of hydrated salted CuSO4 x H2O was dissolved in 500cm3 of water and it's concentration in moldm3 was experimentally found to be 0.072M . Calculate, the molar mass of CuSO4 x H2O and the value of x, the water of crystallization.[Cu=64 S=32 O=16 H=1]
I don't understand it well so please can you solve it
M = 0.072 = 0.072 moles/dm^3 = 0.072 moles/L so in 500 cc (0.500 L) you will have 0.072/2 = 0.036 moles.
moles = grams/molar mass or molar mass = grams/mols. Substitute as follows:
molar mass CuSO4.xH2O = 9 g/0.036 = 250
CuSO4.xH2O = 250. CuSO4 = 160; therefore, 250-160 = 90 and since H2O = 18, then 90/18 = 5. Therefore, the hydrated salt is CuSO4.5H2O
To calculate the molar mass of CuSO4 x H2O and determine the value of x (the water of crystallization), we can use the given information.
From the given information, we can determine the number of moles of CuSO4 in the solution.
Number of moles = concentration (in mol/dm^3) * volume (in dm^3)
Given:
Concentration = 0.072 M
Volume = 500 cm^3 = 0.5 dm^3
Number of moles of CuSO4 = 0.072 M * 0.5 dm^3 = 0.036 moles
Next, we need to find the molar mass of CuSO4 by using the atomic masses provided.
Molar mass of CuSO4 = (atomic mass of Cu) + (atomic mass of S) + 4*(atomic mass of O)
Molar mass of CuSO4 = (64 g/mol) + (32 g/mol) + 4*(16 g/mol)
= 64 g/mol + 32 g/mol + 64 g/mol
= 160 g/mol
Now, we need to calculate the molar mass of the hydrate, CuSO4 x H2O.
To do this, we divide the mass of CuSO4 by the moles of CuSO4 we calculated earlier.
Mass of CuSO4 = molar mass of CuSO4 * number of moles of CuSO4
= 160 g/mol * 0.036 mol
= 5.76 g
Given:
Mass of hydrated salt, CuSO4 x H2O = 9.0 g
Mass of water, H2O = Mass of hydrated salt - Mass of CuSO4
= 9.0 g - 5.76 g
= 3.24 g
Now, we can calculate the moles of water (H2O) in the hydrated salt.
Moles of water = mass of water / molar mass of water
= 3.24 g / (2 g/mol + 16 g/mol)
= 3.24 g / 18 g/mol
= 0.18 moles
Since the formula for the hydrate is CuSO4 x H2O, we know that the ratio of CuSO4 to H2O is 1:1.
Therefore, the value of x is the same as the moles of water, which is 0.18.
So, the molar mass of CuSO4 x H2O is 160 g/mol, and the value of x (the water of crystallization) is 0.18.
To calculate the molar mass of CuSO4 x H2O and determine the value of x, the water of crystallization, we need to use the given information about the mass of the hydrated salt, its concentration, and the density of the solution.
First, let's find the number of moles of the hydrated salt (CuSO4 x H2O). We use the formula:
Moles = (Concentration x Volume) / 1000
Concentration is given as 0.072 M, and the volume is 500 cm3, which we convert to liters by dividing by 1000:
Moles = (0.072 M x 500 cm3) / 1000 = 0.036 moles
Now, to find the molar mass of CuSO4 x H2O, we divide the mass of the hydrated salt by the number of moles:
Molar mass = Mass / Moles
From the question, the mass of the hydrated salt is given as 9.0 g.
Molar mass = 9.0 g / 0.036 moles = 250 g/mol
Therefore, the molar mass of CuSO4 x H2O is 250 g/mol.
Now, let's determine the value of x, the water of crystallization. The molar mass of CuSO4 is 159.6 g/mol (64 g + 32 g + 4x16 g).
To find the mass of water in CuSO4 x H2O, subtract the molar mass of CuSO4 from the molar mass of CuSO4 x H2O:
Mass of water = Molar mass of CuSO4 x H2O - Molar mass of CuSO4
Mass of water = 250 g/mol - 159.6 g/mol = 90.4 g/mol
Since the molar mass of water (H2O) is 18 g/mol (2 x 1 g + 16 g), the mass of water is equivalent to 5 moles (90.4 g/mol ÷ 18 g/mol).
Therefore, the value of x, the water of crystallization, is 5.