Avery large open tank is full of oil whose density is800kg/m3.If the absolute pressure are the bottom of thankis1.81x10 5pa, then what is the depth of oil? (Note the atmospheric pressure is1.01x10 tpa
To calculate the depth of the oil in the large open tank, we need to use the concept of pressure and the density of the oil. The pressure at a certain depth in a fluid is given by the equation:
P = P₀ + ρgh
Where:
- P is the absolute pressure at the bottom of the tank (1.81x10⁵ Pa)
- P₀ is the atmospheric pressure (1.01x10⁵ Pa)
- ρ is the density of the oil (800 kg/m³)
- g is the acceleration due to gravity (9.8 m/s²)
- h is the depth of the oil
Since we want to calculate the depth of the oil, we rearrange the equation to solve for h:
h = (P - P₀) / (ρg)
Let's substitute the given values into the equation:
h = (1.81x10⁵ - 1.01x10⁵) / (800 * 9.8)
Now we can calculate the depth:
h = 8 m
Therefore, the depth of the oil in the tank is 8 meters.