two forces 20N each are inclined at 120degree to 130degree to each other...
To find the resultant force of two forces inclined at an angle to each other, you can use the law of cosines. The law of cosines states that in a triangle, the square of one side is equal to the sum of the squares of the other two sides, minus twice the product of those sides and the cosine of the included angle.
In this case, we have two forces of 20N each, and the angle between them is 120 degrees. Let's label the two forces as force A and force B.
Using the law of cosines, we can calculate the resultant force:
Resultant force^2 = Force A^2 + Force B^2 - 2 * Force A * Force B * cos(angle)
Substituting the values:
Resultant force^2 = 20N^2 + 20N^2 - 2 * 20N * 20N * cos(120 degrees)
Calculating:
Resultant force^2 = 400N^2 + 400N^2 - 2 * 20N * 20N * (-0.5)
= 800N^2 + 400N^2
= 1200N^2
Taking the square root of both sides:
Resultant force = √(1200N^2)
= √(1200) * N
≈ 34.64N
Therefore, the magnitude of the resultant force is approximately 34.64N.
Note: The sign (+/-) of the resultant force can be determined by considering the directions of the individual forces.