A 15 Ohm resistor is in series with a 20 Ohm resistor and a 25 Ohm resistor. What is the equivalent resistance of these elements?
Do you add them all to get the equivalent resistance?
15+20+25= 60, or do you divide 60/3= 20? I'm not sure how to go about this problem.
for resistors in series, just add them up.
R = R1+R2+R3+,,,
for resistors in parallel, it all reciprocals
1/R = 1/R1 + 1/R2 + 1/R3 + ....
surely you have seen these formulas
I haven't since my professor hasn't gone over these for electric circuits, but they're on my quiz, so that's why I asked.
Yeah, it's a summer class, so he was going to show us part two of the electric circuits next week, but the quiz covers the whole chapter and it was due after we covered part one of the electric circuits. I don't know why he does this. I have to rely on a lot of outside sources to help me understand the material.
Update, my professor removed that question from the quiz, and others like it.
He just taught us this right now, and if anyone else is struggling with this problem it is 15+20+25= 60.
To find the equivalent resistance of resistors in series, you need to add their individual resistances together. In this case, you have a 15 Ohm resistor, a 20 Ohm resistor, and a 25 Ohm resistor in series.
So, to find the equivalent resistance, you add these resistances together:
15 + 20 + 25 = 60 Ohms.
Therefore, the equivalent resistance of these three resistors in series is 60 Ohms.