Jordan has a total of one hundred thirty-eight nickels, dimes, and quarters. He has a total of $13.80. He has two times as many dimes as quarters and one-third as many quarters as nickels. How many of each coin does he have?
d = 2 q
n = 3 q
d + n + q = 138
2 q + 3 q + q = 138
q = 138/6 = 23
d = 46
n = 69
now does that satisfy the last equation?
10 d + 5 n + 25 q = 1380
460 + 345 + 575 = 1380, luckily
You came up with this over defined question I wonder?