A force of 2N extends a spring of natural length 2m by0.01m when they arrived, force is 10N.what will be the new length of the spring
F = k x
2 = k * 0.01
k = 2 / 0.01 = 200
10 = 200 x
x = 1/20 = 0.05
total new length = 2.05 meters
F=kx
5 times the force gives 5 times the extension: 0.05
so the new length is 2.05 m