A body of mass 20g moves in a circular path with radius of 10m with a constant speed of 4.0m/s. What is the centripetal force?
per the usual formulas,
a = v^2/r
F = ma
To find the centripetal force acting on the body moving in a circular path, we can use the formula:
F = (m * v^2) / r
Where:
F is the centripetal force
m is the mass of the body
v is the velocity of the body
r is the radius of the circular path
In this case, the mass of the body is given as 20g, which is equivalent to 0.02kg. The radius of the circular path is 10m, and the constant speed of the body is given as 4.0m/s.
Plugging the values into the formula, we get:
F = (0.02kg * (4.0m/s)^2) / 10m
Calculating further, we have:
F = (0.02kg * 16m^2/s^2) / 10m
F = (0.32kg * m^2/s^2) / 10m
F = 0.032kgm^2/s^2 / 10m
F = 0.032N
Therefore, the centripetal force acting on the body is 0.032 Newtons.
To find the centripetal force acting on the body, you can use the formula:
Centripetal force (F) = (mass of the body) x (velocity^2) / (radius of the circular path)
First, let's convert the mass of the body from grams to kilograms:
mass = 20 g = 20/1000 kg = 0.02 kg
Now we can substitute the given values into the formula:
F = (0.02 kg) x (4.0 m/s)^2 / (10 m)
Calculating the values:
F = (0.02 kg) x (16 m^2/s^2) / (10 m)
F = 0.32 N
Therefore, the centripetal force acting on the body is 0.32 N.