Find the root of the equation 2x2_3x_2=0
assuming you meant:
2x^2 - 3x - 2 = 0
it factors:
(2x + 1)(x - 2) = 0
x = -1/2 or x = 2
as you typed it ...
361/2×64-1/2×5°
= (361/2)(64) - (1/2)(5) , ignoring the ° symbol, no idea why it is there.
= (361)(32) - 5/2
= 11552 - 5/2
= 23099/2
If you meant something else, let me know
e.g. is it 361/2 or 36 1/2 ? that is, is it is 180.5 or 36.5 ?
To find the roots of the equation 2x^2 - 3x - 2 = 0, we can use the quadratic formula. The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 2, b = -3, and c = -2.
Substituting these values into the formula, we have:
x = (3 ± √((-3)^2 - 4 * 2 * -2)) / (2 * 2)
Simplifying further:
x = (3 ± √(9 + 16)) / 4
x = (3 ± √25) / 4
Now, we have two possible solutions:
1. Taking the positive square root:
x = (3 + 5) / 4 = 8 / 4 = 2
2. Taking the negative square root:
x = (3 - 5) / 4 = -2 / 4 = -0.5
Therefore, the roots of the equation 2x^2 - 3x - 2 = 0 are x = 2 and x = -0.5.