A bag contains each letter of the alphabet. Find the probability that a randomly selected letter from the bag will not be one of the five vowels.
26 letters, 5 vowels, so
P(~vowel) = 21/26
To find the probability that a randomly selected letter from the bag will not be one of the five vowels, we need to determine the number of favorable outcomes (letters that are not vowels) and the total number of possible outcomes (all letters in the bag).
First, let's determine the number of favorable outcomes. There are 26 letters in the alphabet, and out of those, 5 are vowels (A, E, I, O, U). So, the number of favorable outcomes will be 26 - 5 = 21.
Next, let's determine the total number of possible outcomes. Since the bag contains each letter of the alphabet, there are 26 letters in total.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes
= 21 / 26
Simplifying the fraction, we have:
Probability = 0.8077
Therefore, the probability that a randomly selected letter from the bag will not be one of the five vowels is approximately 0.8077, or 80.77%.
To find the probability that a randomly selected letter from the bag will not be one of the five vowels, we need to determine the number of letters that are not vowels and divide it by the total number of letters in the bag.
There are 26 letters in the alphabet, and 5 of them are vowels (A, E, I, O, U).
To find the number of non-vowel letters, we subtract 5 from 26:
Number of non-vowel letters = 26 - 5 = 21
The probability of selecting a non-vowel letter is the number of non-vowel letters divided by the total number of letters:
Probability = Number of non-vowel letters / Total number of letters
Probability = 21 / 26
Therefore, the probability that a randomly selected letter from the bag will not be one of the five vowels is 21/26.