A 2.8 kg sample of a metal with a specific heat of 0.43KJ/kg°C is heated to 100.0°C then placed in a 50.0 g sample of water at 30.0°C. What is the final temperature of the metal and the water?
heat lost by hot metal + heat gained by cool water = 0
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tintial)] = 0
mass metal is given.
specific heat metal is given
Tfinal metal is to be determined
mass H2O is given
specific heat H2O is not given. You look that up in your notes/text/web.
Tfinal H2O is to be determined.
Tintial H2O is given
Plug in all these numbers and solve for Tfinal. Of course you realize that Tfinal for the metal and Tfinal for the H2O is the same. Post your work if you get stuck.