Question

. A student moves along the boundary of a square field of side 10 In in 40 see. If he started from one of the corners of the square what will be the magnitude of displacement of the student at the end of 2 minutes and 20 seconds from his initial position?

Answer 1

2'20" = 130 = 3*40+10 seconds, so he is now only 3/4 of a side from his starting position. That would be 30 "ln", whatever they are.