A block and tackle system of pulley has a V_{R} = 8 and MA = 7 A 400N object is lifting using the machine through a height of 1.5m. What is a) the work done on the load? B) the effort force? e) The distance moved by the effort force?
of rodius
To solve this problem, we need to use the formulas for work, mechanical advantage, and the relationship between effort force and load force in a block and tackle system.
a) The work done on the load can be calculated using the formula:
Work = Force x Distance
In this case, the force is the load force applied to the object (400N) and the distance is the height through which the load is lifted (1.5m). So:
Work = 400N x 1.5m = 600 Joules
Therefore, the work done on the load is 600 Joules.
b) The effort force can be calculated using the formula for mechanical advantage (MA):
MA = Load Force / Effort Force
In this case, the load force is 400N and the mechanical advantage is given as 7. We need to rearrange the formula to solve for the effort force:
Effort Force = Load Force / MA
Effort Force = 400N / 7 = 57.14N (rounded to two decimal places)
Therefore, the effort force is approximately 57.14N.
c) The distance moved by the effort force can be calculated by dividing the distance moved by the load by the mechanical advantage:
Distance by Effort Force = Distance by Load / MA
Distance by Effort Force = 1.5m / 7 = 0.214m (rounded to three decimal places)
Therefore, the distance moved by the effort force is approximately 0.214m.
Note: In the given problem, there is reference to "V_{R} = 8", which is not clear how it relates to the problem or the calculations needed. Please clarify if there is any additional information or context related to V_{R} that needs to be considered for solving the problem.