If the density of pure acetic acid is 1.005g cm, what is its molarity?
You need to learn the difference between cm and cc or cm^3. cm is a distance. cc is a volume. 1 cc = 1 mL also.
density acetic acid = grams/mL = 1.005 g/cc = 1.005 g/mL.
mass of 1 L of this acid = 1.005 g/mL x 1000 mL = 1005 g.
How many moles is that? moles = g/molar mass = 1005/60 = ?
Then M = moles/L
Well, let's see here... I'm not sure what trickery you're up to, but I'll give it a go!
To find the molarity of acetic acid, we're going to need the molar mass of acetic acid, CH3COOH. And since acetic acid is a combination of carbon, hydrogen, and oxygen atoms, I'd say it sounds like a molecular cocktail.
Grabbing my virtual chemistry mixing set, I calculate that the molar mass of acetic acid is approximately 60 grams per mole. Now, with the density you provided (1.005 grams per cubic centimeter), we can perform some circus calculations!
To determine the molarity, we need to convert the density of the acetic acid into units of moles per liter (mol/L). Since the density is given in grams per cubic centimeter, let's tackle that first.
Given that density equals mass divided by volume, we can rearrange the formula to find the volume: volume = mass/density.
Plugging in the given density of 1.005 g/cm³, we divide the molar mass of acetic acid (60 g/mol) by the density to find the volume in cm³. To convert this volume to liters, we divide by 1000. Finally, since we want the molarity, we divide the amount of substance (moles) by the volume (in liters).
Calculations are complete! After juggling the numbers, the approximate molarity of pure acetic acid is 1 M.
Remember, clown logic isn't always perfect, so I recommend double-checking my calculations with a reliable chemistry source!
To calculate the molarity of a substance, we need to know the density and the molar mass.
Step 1: Find the molar mass of acetic acid (CH3COOH).
The molar mass of carbon (C) is 12.01 g/mol.
The molar mass of hydrogen (H) is 1.008 g/mol.
The molar mass of oxygen (O) is 16.00 g/mol.
Calculating the molar mass of acetic acid:
(2 x C) + (4 x H) + (2 x O) = (2 x 12.01) + (4 x 1.008) + (2 x 16.00) = 60.05 g/mol.
Step 2: Calculate the molarity of acetic acid.
First, convert the given density from g/cm^3 to g/mL because the molarity is usually expressed in terms of moles per liter (mol/L).
1 cm^3 = 1 mL
Therefore, the density of pure acetic acid is 1.005 g/cm^3 = 1.005 g/mL.
Now, we know that the molarity (M) is given by the formula:
Molarity (M) = (density in g/mL) / (molar mass in g/mol)
Substituting the values:
Molarity (M) = 1.005 g/mL / 60.05 g/mol.
Calculating the molarity:
Molarity (M) = 0.01673 mol/L.
Therefore, the molarity of pure acetic acid is approximately 0.01673 mol/L.
To find the molarity of a substance, we need to know its density and molar mass. The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol.
First, let's convert the density from grams per cubic centimeter (g/cm) to grams per milliliter (g/mL), since the unit for molarity is moles per liter (mol/L). There are 1,000 milliliters in one liter, so:
Density in g/mL = Density in g/cm^3 = 1.005 g/cm^3
Next, we need to convert the density to molarity. The molarity (M) is defined as the number of moles of solute per liter of solution.
To convert from grams to moles, we divide the mass of the substance by its molar mass:
Molarity (M) = (Density in g/mL) / (Molar mass in g/mol)
Molarity (M) = 1.005 g/mL / 60.05 g/mol
Molarity (M) = 0.0168 mol/mL
Finally, we need to convert milliliters to liters by dividing by 1,000:
Molarity (M) = 0.0168 mol/mL / 1000 mL/L
Molarity (M) = 0.0168 mol/L
Therefore, the molarity of pure acetic acid is approximately 0.0168 M.