A gas sample occupies a volume of 2000L at 40 degrees celcius .What volume will it occupy at STP?
You don't provide P so I assume it is 1 atm.
Use V1/T1 = V2/T2
V1 = 2000 L
T1 = 40 + 273 = ? K
V2 = ?
T2 = 273
jajah
To find the volume of a gas sample at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation: PV = nRT. Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
To solve this problem, we first need to convert the temperature from Celsius to Kelvin. The Kelvin temperature scale starts at absolute zero, which is 0 Kelvin (K). To convert Celsius to Kelvin, we use the formula: K = °C + 273.15.
In this case, the temperature is 40 degrees Celsius, so in Kelvin, it will be:
T = 40 + 273.15
T = 313.15 K
Next, we need to define the conditions for STP. At standard temperature and pressure, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (0 degrees Celsius).
Now we can set up our equation and solve for the volume at STP:
(P1 * V1) / (T1) = (P2 * V2) / T2
Since the original volume is given as 2000L at 40 degrees Celsius, we have:
(P1 * 2000) / 313.15 = (1 * V2) / 273.15
We can now solve for V2, the volume at STP:
V2 = (2000 * 273.15) / 313.15
V2 ≈ 1740.1 L
Therefore, the gas sample will occupy a volume of approximately 1740.1 liters at STP.