An aeroplane flies from Geneva on a bearing of 031° for 200 km. It then changes course and flies for
140 km on a bearing of 075°. Find:
a
the distance of Geneva from the aeroplane
b the bearing of Geneva from the aeroplane.
Does anyone know how to solve this problem?
Thank you
just separate each vector into its x- and y-components.
Add them up to get the final location.
Draw a sketch of the triangle and use the law of cosines to find the third side.
Then figure the x- and y-distances from there back to Geneva, and use them to get the final bearing.
Post your work if you get stuck.