CH4 + 2O 2 ---> 2H 2O + CO 2
How many grams of Co2 are produced by combustion of 64.0 of CH4?
Show all work...
CH4 = 12 +4 = 16 grams / mol
so
we have 4 = 64 /16 mols of CH4
so we get 4 mols of CO2
4 *(12 + 32) = 4*44 = 176 grams of CO2
SEQUESTER IT !!!
Thank you! not sure what sequester means but, Thank you!
Get plants to eat the CO2 or hide it under the earth so it does not reflect warmth back toward earth from the atmosphere and cook us all. Sequester means sort of pack away.
To determine the number of grams of CO2 produced by the combustion of 64.0 grams of CH4, we need to follow a few steps.
Step 1: Determine the molar mass of CH4
The molar mass of CH4 can be calculated by adding up the atomic masses of the elements in the compound. Let's calculate it:
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol (There are 4 hydrogen atoms in CH4)
Molar mass of CH4 = (12.01 g/mol × 1) + (1.01 g/mol × 4) = 16.05 g/mol
Step 2: Convert grams of CH4 to moles
To convert grams of CH4 to moles, we need to use the molar mass:
Number of moles of CH4 = (64.0 g CH4) / (16.05 g/mol CH4) = 3.99 mol CH4 (rounded to two decimal places)
Step 3: Apply the stoichiometry of the balanced equation
According to the balanced equation given:
CH4 + 2O2 ---> 2H2O + CO2
From the equation, we can see that 1 mol of CH4 reacts to produce 1 mol of CO2. Therefore, the number of moles of CO2 produced will be the same as the number of moles of CH4 consumed. So, the number of moles of CO2 produced is also 3.99 mol.
Step 4: Convert moles of CO2 to grams
To convert moles of CO2 to grams, we can use the molar mass of CO2. The molar mass of CO2 can be calculated similarly to how we calculated the molar mass of CH4:
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol (There are two oxygen atoms in CO2)
Molar mass of CO2 = (12.01 g/mol) + (16.00 g/mol × 2) = 44.01 g/mol
Now, we can calculate the mass of CO2 produced:
Mass of CO2 = (3.99 mol CO2) × (44.01 g/mol CO2) = 177.34 g CO2 (rounded to two decimal places)
Therefore, the mass of CO2 produced by the combustion of 64.0 grams of CH4 is approximately 177.34 grams.