I am an even number between 50 and 60 . The sum of my digits is 11 . Then who am I ?

According to the question, the number lies between 50 and 60.

This means that the digit at the tens place must be 5, because for 60 sum of digits is 6 + 0 = 6

Also, according to the question, the digits sum up to give a total of 11.

a = tens place digit

b = one digit

tens place digit is 5

5 + b = 11

b = 11 - 5 = 6

Your number is 56

By the way even numbers 50 - 60 are:

50

Sum of digits = 5 + 0 = 5

52

Sum of digits = 5 + 2 = 7

54

Sum of digits = 5 + 4 = 9

56

Sum of digits = 5 + 6 = 11

58

Sum of digits = 5 + 8 = 13

60

Sum of digits = 6 + 0 = 6

Only the number 56 satisfies the condition that the sum of the digits is 11.

Ffc

Well, well, well! You must be the magnificent 58! Your digits are doing a great balancing act, adding up to 11 and landing you right in the sweet spot between 50 and 60. Keep up the good work, number superstar!

To find the number, we can start by listing all the even numbers between 50 and 60: 52, 54, 56, 58.

Next, we need to check the sum of the digits for each number:

For 52, the sum of the digits is 5 + 2 = 7.
For 54, the sum of the digits is 5 + 4 = 9.
For 56, the sum of the digits is 5 + 6 = 11.
For 58, the sum of the digits is 5 + 8 = 13.

Since the sum of the digits for 56 is 11, that number fits the given conditions. Therefore, you are the number 56.

To find the number that satisfies the given conditions, we can start by listing down the possible even numbers between 50 and 60: 52, 54, 56, and 58.

Next, we need to check the sum of the digits for each of these numbers. Let's do that:

For 52: 5 + 2 = 7 (not 11)
For 54: 5 + 4 = 9 (not 11)
For 56: 5 + 6 = 11 (sum matches!)
For 58: 5 + 8 = 13 (not 11)

Therefore, the number that is an even number between 50 and 60 and has a sum of digits equal to 11 is 56.