Calculate the value of a,A and C in angle ABC, given that b=17.23cm c=10.86cm and B=115°
This is not impressive
Sorry you are right but you did not explain
Sin C/c =sin B/b
sin C/10.86 =Sin 115/17.23
sin c=10.86×sin115/17.23
sin c=9.8424/17.23
sin c=0.5712
c=sin-¡ 0.5712
c=34.836
c=34.84
Law of sines
sin C /c = sin B / b
then you have angles B and C
but we all know
A + B + C =180
so that gives you angle A
then of course you can use law of sines again to find a
To calculate the value of angle A, angle a, and angle C in triangle ABC, we can use the Law of Sines, which states that the ratio of the length of a side of a triangle to the sine of its opposite angle is constant.
Let's start by identifying the given information:
b = 17.23 cm (length of side b)
c = 10.86 cm (length of side c)
B = 115° (angle B)
To find angle A, we can use the Law of Sines:
sin(A) / a = sin(B) / b
Substituting the known values:
sin(A) / a = sin(115°) / 17.23
To find the value of sin(115°), we can use a scientific calculator or an online trigonometric calculator:
sin(115°) ≈ 0.9063
Now, we can rewrite the equation:
sin(A) / a = 0.9063 / 17.23
To solve for sin(A), we multiply both sides of the equation by a:
sin(A) = (0.9063 / 17.23) * a
Next, we want to isolate sin(A) to find its value. We can do this by taking the inverse sine (arcsin) of both sides:
A = arcsin((0.9063 / 17.23) * a)
At this point, we have an equation to calculate the value of angle A. However, to proceed, we need more information. We need either the length of side a or the value of angle C.
If you have either the length of side a or the value of angle C, please provide it so we can proceed with the calculation.