# chemistry

acid: HCI 0.10 M
Base:NaOH O.050 M

3 ml of HCI was used.

Calculate the volume of base required to reach the equivalence point of this titration.

Somewhere in the finding the solution, i have to use the fact that
Moles HCl = moles NaOH.

this is what i have so far:
Volume of base= [(Molarity of NaOH)( Volume of NaOH)]/Molarity of HCI
(0.050 M)( mL) = (0.10 M)(x mL)

when do i use Moles HCl = moles NaOH.

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3. 👁 132

MolesHCL=MolesNaOH
VolumeHCl(MolarityHCL)=Volumebase*MolarityBAse

Volumebase=VolumeHCl*MolarityHCl/MolarityNaOH

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