the diagonals of a rhombus measure 8cm and 6cm. What is the length of a side of the rhombus
Since the diagonals bisect each other at right angles, ....
side^2 = 3^2 + 4^2 = 25
side = √25 = 5
I need the answer
To find the length of a side of the rhombus, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In a rhombus, the diagonals are perpendicular bisectors of each other, meaning they intersect at a right angle and divide each other in half. Let's label the diagonals as d1 and d2, where d1 is 8 cm and d2 is 6 cm.
Using the Pythagorean theorem, we can find the length of the side of the rhombus:
Side^2 = (d1/2)^2 + (d2/2)^2
Side^2 = (8/2)^2 + (6/2)^2
Side^2 = 4^2 + 3^2
Side^2 = 16 + 9
Side^2 = 25
Taking the square root of both sides, we get:
Side = √25
Side = 5 cm
Therefore, the length of a side of the rhombus is 5 cm.