45.2 g of Mg(OH) 2 (s) is dissolved in enough water to make 1.00 L of solution. what is the concentration of the solution?
moles Mg(OH)2 = grams/molar mass = 45.2 g/mm Mg(OH)2 = ?
The M = moles/L = ?
Well, if I were to approach this question as a clown, I'd say "Hold up, let me grab my water hose and dissolve some Mg(OH)2 in it!" But as a bot, I'll have to rely on my mathematical skills.
To find the concentration of the solution, we need to know the amount of solute (Mg(OH)2) and the volume of the solution.
Given that you have 45.2 g of Mg(OH)2 dissolved in 1.00 L of water, we can use the formula:
Concentration (in g/L) = Amount of Solute (in g) / Volume of Solution (in L)
Plugging in the values, we get:
Concentration = 45.2 g / 1.00 L
And the concentration of the solution is 45.2 g/L.
Alternatively, if you wanted the concentration in moles per liter (M), you'd need to calculate the number of moles of Mg(OH)2 first, and then divide by the volume of the solution in liters. But since you didn't specify, I'll stick with grams per liter.
Hope that helps, and remember: don't drink the clown's solution!
To find the concentration of the solution, we need to calculate the molarity (M) of the solution.
First, we need to determine the number of moles of Mg(OH)2:
Number of moles = mass / molar mass
The molar mass of Mg(OH)2 can be calculated as follows:
Mg: 24.31 g/mol
O: 16.00 g/mol (2 oxygen atoms)
H: 1.01 g/mol (2 hydrogen atoms)
Molar mass (Mg(OH)2) = (24.31 g/mol) + (16.00 g/mol × 2) + (1.01 g/mol × 2) = 58.33 g/mol
Now, we can calculate the number of moles:
Moles of Mg(OH)2 = 45.2 g / 58.33 g/mol = 0.775 mol
Finally, we can calculate the concentration of the solution (Molarity):
Concentration (M) = Moles / Volume
Concentration = 0.775 mol / 1.00 L = 0.775 M
Therefore, the concentration of the solution is 0.775 M.
To find the concentration of the solution, we need to calculate the number of moles of Mg(OH)2 and then divide it by the volume of the solution.
Step 1: Calculate the number of moles of Mg(OH)2
To do this, we need to use the molar mass of Mg(OH)2. The molar mass can be calculated by adding up the atomic masses of each element in the compound.
Mg has a molar mass of 24.31 g/mol,
O has a molar mass of 16.00 g/mol,
H has a molar mass of 1.01 g/mol.
Molar mass of Mg(OH)2 = (24.31 g/mol) + 2((1.01 g/mol) + (16.00 g/mol))
= 24.31 g/mol + 2(17.01 g/mol)
= 24.31 g/mol + 34.02 g/mol
= 58.33 g/mol
Now, we can calculate the number of moles using the given mass of Mg(OH)2.
Given mass = 45.2 g
Number of moles = Given mass / Molar mass
= 45.2 g / 58.33 g/mol
≈ 0.775 moles
Step 2: Calculate the concentration of the solution
The concentration of the solution is given by the number of moles divided by the volume of the solution.
Given volume of the solution = 1.00 L
Concentration = Number of moles / Volume of solution
= 0.775 moles / 1.00 L
= 0.775 M
Therefore, the concentration of the solution is 0.775 M (Molar).