An arrow is shot at 30.0° angle with the horizontal. It has a velocity of 49 m/s.
a. How high will it go?
b. What is the total flight time (between launch and touching the ground) of the object?
c. What horizontal distance will the arrow travel?
Vi = 49 sin 30 = 49/2 initial speed up
v = Vi - g t
v = 0 at top
so
time at top = 49 / 2 g
so total time = 49 / g
u= 49 cos 30
range = u * total time