Find the p-value of the test

H0 : μ = 100 when Hα : μ > 100 and z = 2.17

A. .0251
B. .0150
C. .0199
D. .0193

We observe that the test is right-tailed since the alternate hypothesis suggests that the true mean might be greater than the null hypothesis of 100.

According to the z-table, a z-score of z=2.17 corresponds to a p-value of p=0.9850

Because the test is right-tailed, we subtract our p-value from 1 and get 0.0150 as our p-value for the test.

Thus, B is correct.

Since our p-value is less than the assumed critical value of α=0.05, it is very likely that the null hypothesis is true and that the alternate hypothesis is not true. This means the null hypothesis fails to be rejected, but the alternate hypothesis is rejected.