Find the p-value of the test
H0 : μ = 100 when Hα : μ > 100 and z = 2.17
A. .0251
B. .0150
C. .0199
D. .0193
We observe that the test is right-tailed since the alternate hypothesis suggests that the true mean might be greater than the null hypothesis of 100.
According to the z-table, a z-score of z=2.17 corresponds to a p-value of p=0.9850
Because the test is right-tailed, we subtract our p-value from 1 and get 0.0150 as our p-value for the test.
Thus, B is correct.