Simplify the expression.
(n^4)^8
A. n^48
B. n^32
C. n^12
D. n^4
Please help! I don't know which one it is.
(n^4)^8 = n^(4*8) = n^32
consider something like
(n^4)^3 = (n^4)(n^4)(n^4) = n^(4+4+4) = n^12
(n^a)^b = n^(a*b)
Thank you so much you were 100% correct it was n^32
Thank you again! : )