Question

In the balanced reaction shown below, what is the ratio of lead nitrate (Pb(NO3)2) to potassium iodide (KI)?

Pb(NO3)2 + 2KI --> PbI2 + 2KNO3

B. 3:2
C. 3:1 <-----my answer
D. 1:2

Answer 1

I would write 1:2 since 1 mol Pb(NO3)2 = 2 moles KI.