A rectangle with a perimeter of 78 and a length that is 3 more than it’s width.Find the width,length,and the area.
W + L = 78 / 2
L = W + 3
substituting ... W + W + 3 = 39
solve for W , then substitute back to find L
area = W * L
L = W + 3
substituting ... W + W + 3 = 39
solve for W , then substitute back to find L
area = W * L