If a sample of gas occupies 6.8 L at 325 degrees C, what will its volume be at 25 degrees C if the pressure does not change?
Since PV=kT, you have, if P is constant,
V/T = k/P, a constant
You want V such that
V/(25+271) = 6.8/(325+271)
oops. typo
That 271 is a 273 in both instances.
oops. nice catch.
Guess I got -273.15 confused with -271.35
...
or sump'n
To find the volume of gas at a different temperature with the pressure remaining constant, we can use the Charles's Law, which states that for a given amount of gas at a constant pressure, the volume of the gas is directly proportional to its absolute temperature.
To solve the problem, we need to convert the temperatures from Celsius to Kelvin since the equation requires temperature in Kelvin.
To convert temperatures from Celsius to Kelvin, we use the following equation:
Kelvin = Celsius + 273.15
Let's convert the temperatures:
Initial temperature (in Kelvin) = 325 + 273.15 = 598.15 K
Final temperature (in Kelvin) = 25 + 273.15 = 298.15 K
Now, we can use the formula:
(Volume 1) / (Temperature 1) = (Volume 2) / (Temperature 2)
Plugging in the values:
(6.8 L) / (598.15 K) = (Volume 2) / (298.15 K)
Cross-multiplying, we get:
(6.8 L) * (298.15 K) = (Volume 2) * (598.15 K)
Now, we can solve for Volume 2:
Volume 2 = (6.8 L) * (298.15 K) / (598.15 K)
Calculating this equation gives us the final answer.