What is the sum of the distinct prime factors of 90?
90 = 2*3*3*5
So the "distinct" prime factors of 90 are 2,3, and 5
So what is 2+3+5 ?
To find the sum of the distinct prime factors of a number, we first need to find the prime factors of that number.
To find the prime factors of 90, let's divide it by the smallest prime number, which is 2. Since 90 is divisible by 2, we get 90 ÷ 2 = 45.
Now we repeat the process with the quotient, which is 45. Again, we divide it by 2: 45 ÷ 2 = 22.5. Since 22.5 is not a whole number, we move on to the next prime number, which is 3. Dividing 45 by 3 gives us 45 ÷ 3 = 15.
Next, we divide 15 by 3 again, resulting in 15 ÷ 3 = 5. This time, we cannot divide 5 any further, so we stop here.
The prime factorization of 90 is 2 × 3 × 3 × 5.
To find the distinct prime factors, we simply list each prime factor once: 2, 3, and 5.
Finally, we add these distinct prime factors together: 2 + 3 + 5 = 10.
Therefore, the sum of the distinct prime factors of 90 is 10.
To find the sum of the distinct prime factors of 90, we need to find the prime factorization of 90 first.
Step 1: The first prime number is 2. Divide 90 by 2, we get 45.
Step 2: The second prime number is also 2. Divide 45 by 2, we get 22.5, which is not a whole number. So we need to move on to the next prime number.
Step 3: The next prime number is 3. Divide 45 by 3, we get 15.
Step 4: The next prime number is 3 again. Divide 15 by 3, we get 5, which is a prime number.
Therefore, the prime factorization of 90 is 2 * 3 * 3 * 5.
The distinct prime factors are 2, 3, and 5.
To find the sum of these distinct prime factors, add them together:
2 + 3 + 5 = 10.
Therefore, the sum of the distinct prime factors of 90 is 10.