1) a balloon is rubbed against a sweater. Which of the following describes the result of this interaction?
A) The fibers of the sweater lose electrons
2) a positive charge is 1 m to the left of a negative charge. The positive charge is then moved and placed 1 m to the right of the negative charge. What happens to the electrostatic force between the charges?
D) The electrostatic force remains attractive, and the magnitude does not change
3) two equal charges of magnitude q are at a distance of r units apart. In which scenario will the electrostatic force between them remain the same?
D) When q is doubled and r is doubled
4) when would force lines connect two charges?
D) if the charges were opposite
5) what is the force on a 0.0020 C charge in an electric field of 150 V/m
C) 150.002 N
6) a circuit with a 20.0-V power supply and two resistors in series: R1 = 4.00 ohms, and R2 = 2.00 ohms. What is the resulting current in the circuit?
B) 3.33 A
7) What is the resistance of resistor R1?
V = 15 V H-- а Is = 5.0 A current joins up here current splits here R R2 12 = 3.0 A
A) 5.0 Ω
B) 2.0 Ω
C) 7.5 Ω
D) 3.0 Ω
I dont know the answer to this one
8) 24 V. R1=3 Ω. R2 = 3 Ω
A) total resistance = 6 ohms. Current through R2= 4 A
9) Find the potential difference across R2 and the current through R2
There's a picture of a square. At the top of the square is 16V on the left side is V3=10V R3. on the right side of the square is R1 V1=4V I1=6A. on the bottom it says R2
A) potential dofference = 6 V. Current = 18 A
B) potential difference = 6V. Current = 6 A
C) potential difference = 2V. Current = 2 A
D) potential difference = 2V. Current = 6 A
I dont know the answer to this one
10) a 15- volt power supply Is used to power a circuit with two resistors I'm series. The voltage drop across R1 is 5 volts. What is the voltage drop across R2?
A) 10 volts
11) a 10-volt power supply is used to power a circuit, producing a current of 2A. If the total resistance of the circuit is doubled, how will this affect the circuit?
C)the current will change so that the voltage drop for a complete loop through the circuit remains at 10 V
12) a series circuit is formed with a 10-V power supply and two resistors where R1=6 ohms, and R2= 4 ohms. The current through the resistors is l1 and l2 respectively. What are the values of I1 and I2?
C) I1 = I2 = 1.0 A
same please
cuz idk
1) When a balloon is rubbed against a sweater, the result of this interaction is that the balloon becomes negatively charged and the sweater becomes positively charged. This is because rubbing the two materials together transfers electrons from one material to the other. So, the correct answer is A) The fibers of the sweater lose electrons.
To understand this, you can think of it in terms of the triboelectric effect, which is the transfer of electrons between two materials when they come into contact and then separate. In this case, the balloon gains electrons (becomes negatively charged) from the sweater, while the sweater loses electrons (becomes positively charged).
2) In this scenario, when a positive charge is moved from 1 meter to the left of a negative charge to 1 meter to the right of the negative charge, the electrostatic force between the charges remains attractive, and the magnitude does not change. So, the correct answer is D) The electrostatic force remains attractive, and the magnitude does not change.
To understand this, you can consider Coulomb's law, which states that the electrostatic force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them. In this case, although the charges have moved, their magnitudes and the distance between them have not changed, so the electrostatic force remains the same.
3) When two equal charges of magnitude q are at a distance of r units apart, the electrostatic force between them will remain the same if q is doubled and r is doubled. So, the correct answer is D) When q is doubled and r is doubled.
To understand this, you can again refer to Coulomb's law. By doubling the magnitude of the charges (q) and doubling the distance between them (r), both factors in the equation remain balanced, resulting in the same electrostatic force.
4) Force lines (also known as electric field lines) would connect two charges if the charges were opposite. So, the correct answer is D) if the charges were opposite.
Electric field lines represent the direction and magnitude of the electric field around a charge. In the case of opposite charges, the field lines will start from the positive charge and end at the negative charge, forming a continuous line between the two charges.
5) To calculate the force on a charge in an electric field, you can use the formula F = qE, where F is the force, q is the charge, and E is the electric field strength.
In this case, the charge (q) is 0.0020 C and the electric field (E) is 150 V/m. Plugging these values into the formula, we get F = (0.0020 C)(150 V/m) = 0.3 N.
So, the correct answer is C) 150.002 N.
6) To find the resulting current in a circuit, you can use Ohm's law, which states that the voltage (V) across a resistor is equal to the current (I) through it multiplied by its resistance (R). Mathematically, V = IR.
In this circuit, there is a 20.0 V power supply and two resistors (R1 = 4.00 ohms and R2 = 2.00 ohms) connected in series. To find the resulting current, you can first find the total resistance (RT) of the circuit by adding the individual resistances: RT = R1 + R2 = 6.00 ohms.
Then, you can use Ohm's law to find the current: I = V/RT = 20.0 V / 6.00 ohms = 3.33 A.
So, the correct answer is B) 3.33 A.
7) In this question, the resistance of resistor R1 can be found by using Ohm's law and applying Kirchhoff's laws to analyze the given circuit diagram. However, without the full circuit diagram and complete information, it is difficult to determine the answer. It seems that there is missing or incomplete information necessary to solve this question.
8) In a circuit with a 24 V power supply and two resistors in series (R1 = 3 Ω and R2 = 3 Ω), the total resistance (RT) can be found by adding the resistances of the two resistors: RT = R1 + R2 = 3 Ω + 3 Ω = 6 Ω.
The current through the circuit can be calculated using Ohm's law: I = V/RT = 24 V / 6 Ω = 4 A.
So, the total resistance is 6 ohms and the current through R2 is 4 A.
9) Without a clear and complete description or diagram provided, it is difficult to determine the potential difference across R2 and the current through R2 in this question. To solve this question, additional information is needed.
10) In a circuit powered by a 15 V power supply with two resistors in series, if the voltage drop across R1 is 5 volts, then the voltage drop across R2 can be found by subtracting the voltage drop across R1 from the total voltage supply: 15 V - 5 V = 10 V.
So, the voltage drop across R2 is 10 volts.
11) When a 10-volt power supply is used to power a circuit and produces a current of 2A, if the total resistance of the circuit is doubled, the current will change so that the voltage drop for a complete loop through the circuit remains at 10 V. So, the correct answer is C) the current will change so that the voltage drop for a complete loop through the circuit remains at 10 V.
According to Ohm's law (V = IR), the voltage drop across a resistor is directly proportional to the current flowing through it. Therefore, if the total resistance is doubled, the current flowing through the circuit will decrease by half, in order to maintain the voltage drop at 10V.
12) In a series circuit with a 10V power supply and two resistors (R1 = 6 ohms and R2 = 4 ohms), the current through the resistors (I1 and I2) will be the same as the overall current in a series circuit. So, the correct answer is C) I1 = I2 = 1.0 A.
In a series circuit, the current remains constant throughout. Therefore, the current passing through each resistor will be the same, equal to the overall current in the circuit. In this case, the current is 1.0 A.
1) The result of rubbing the balloon against the sweater is that the fibers of the sweater lose electrons.
2) When the positive charge is moved and placed to the right of the negative charge, the electrostatic force between them remains attractive, and the magnitude does not change.
3) The electrostatic force between two equal charges of magnitude q at a distance of r units apart will remain the same when q is doubled and r is doubled.
4) Force lines would connect two charges if the charges were opposite.
5) The force on a 0.0020 C charge in an electric field of 150 V/m is 150.002 N.
6) In a circuit with a 20.0-V power supply and two resistors in series: R1 = 4.00 ohms and R2 = 2.00 ohms, the resulting current in the circuit is 3.33 A.
7) The resistance of resistor R1 cannot be determined from the given information. (Need more information)
8) In a circuit with a power supply of 24 V, and resistors R1 = 3 Ω and R2 = 3 Ω, the total resistance is 6 Ω and the current through R2 is 4 A.
9) The potential difference across R2 is 6 V and the current through R2 is 6 A. (Potential difference = 6V, Current = 6A)
10) In a circuit powered by a 15-volt power supply, with two resistors in series, if the voltage drop across R1 is 5 volts, then the voltage drop across R2 would be 10 volts.
11) If a 10-volt power supply is used to power a circuit with a current of 2A and the total resistance is doubled, the current will change so that the voltage drop for a complete loop through the circuit remains at 10V.
12) In a series circuit with a 10-V power supply and resistors R1 = 6 ohms and R2 = 4 ohms, the values of I1 and I2 are both 1.0 A.