For peak A, with retention time, tR, of 2.90 min and sigma = 2.50 sec, calculate the peak width at half height, w1/2, in minutes.
Using the result from above, calculate the resolution of Peak A and Peak B, if the retention time of Peak B is 3.50 min and w1/2 of 0.190 min.
To calculate the peak width at half height (w1/2) in minutes, you can use the formula:
w1/2 = σ * (2 * √(2 * ln(2)))
Given that the retention time (tR) of Peak A is 2.90 min and sigma (σ) is 2.50 sec, we need to convert sigma to minutes before plugging it into the formula.
1 min = 60 sec, so we can convert sigma as follows:
σ = 2.50 sec / 60 sec/min = 0.0417 min
Now we can substitute the values into the formula to find w1/2:
w1/2 = 0.0417 min * (2 * √(2 * ln(2)))
Calculating this expression, w1/2 for Peak A is approximately 0.167 min.
To calculate the resolution between Peak A and Peak B, we can use the following formula:
Resolution = (tB - tA) / (0.5 * (w1/2A + w1/2B))
Given that the retention time (tB) of Peak B is 3.50 min and w1/2 for Peak B is 0.190 min, we plug in the values:
Resolution = (3.50 min - 2.90 min) / (0.5 * (0.167 min + 0.190 min))
Calculating this expression, the resolution between Peak A and Peak B is approximately 3.75.