What is the force on a 0.0020 C charge in an electric field of 150 V/m?
A) 1.3 x 10^-5 N
B) 0.30 N
C) 150.002 N
D) 7.5 x 10^5 N
Its B
To find the force on a charge in an electric field, we can use the equation:
Force (F) = Charge (Q) x Electric Field (E)
Given:
Charge (Q) = 0.0020 C
Electric Field (E) = 150 V/m
Plugging the given values into the equation, we get:
Force (F) = 0.0020 C x 150 V/m
Calculating the product, we find:
F = 0.3 N
Therefore, the correct answer is option B) 0.30 N.
To find the force on a charged object in an electric field, you can use the equation:
F = qE
Where:
F is the force on the charge,
q is the magnitude of the charge, and
E is the strength of the electric field.
In this case, the magnitude of the charge is given as 0.0020 C and the strength of the electric field is given as 150 V/m.
Now, substitute the given values into the equation:
F = (0.0020 C) * (150 V/m)
Multiply the charge and the electric field:
F = 0.3 N
Therefore, the force on the 0.0020 C charge in an electric field of 150 V/m is 0.30 N.
So, the correct answer is B) 0.30 N.