A mass of 0.750 kg is hung from a vertical spring with a spring constant of 20 N/m. After coming to equilibrium the mass is then pulled down an additional distance 10 cm and then released from rest. The mass then oscillates from position 3 to 4 to 5 to 4 and back to 3 over and over.

A) List the types of nonzero energy that the system has at xmin (Position 5). B) Calculate xeq.
C) Calculate hmax.
D) Calculate the total energy of the system at xmax (Position 3).
E) Calculate the maximum speed.
F) Calculate the amounts of EK, Eg, and ES when the mass is 4.00 cm above the equilibrium position.
G) Explain two ways that the maximum speed can be decreased.

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A) At position 5 (xmin), the system has potential energy (Eg) and elastic potential energy (ES). B) xeq can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from equilibrium. In this case, xeq would be the equilibrium position where the mass comes to rest. C) hmax can be calculated using the amplitude of oscillation, which is the maximum displacement from the equilibrium position. D) The total energy of the system at position 3 (xmax) can be calculated by summing the kinetic energy (EK) and potential energy (Eg) of the mass. E) The maximum speed can be calculated using the equation for simple harmonic motion, where the maximum speed is equal to the amplitude times the angular frequency. F) When the mass is 4.00 cm above the equilibrium position, it has kinetic energy (EK), gravitational potential energy (Eg), and elastic potential energy (ES). G) The maximum speed can be decreased by reducing the amplitude of oscillation or by increasing the damping in the system.