If the wavelength of the wave is increased to 10m while its speed remains at 600 m/s, what would happen to the frequency of the wave?
To determine what would happen to the frequency of the wave when the wavelength is increased to 10m while the speed remains at 600 m/s, we can use the equation for wave speed:
Wave Speed = Frequency × Wavelength
Since the speed remains constant at 600 m/s, if the wavelength increases, the frequency must decrease in order to maintain the same wave speed.
Let's denote the original frequency as f1 and the new frequency as f2. We can write the equation for the original wave as:
600 m/s = f1 × λ1
where λ1 is the original wavelength.
Similarly, for the new wave with the increased wavelength of 10m, the equation would be:
600 m/s = f2 × 10m
Since the speed remains the same, we can equate the two equations to find the relationship between the frequencies:
f1 × λ1 = f2 × 10m
Now, we can rearrange the equation to solve for f2:
f2 = (f1 × λ1) / 10m
From this equation, we can see that if the wavelength increases to 10m while the speed remains at 600 m/s, the frequency of the wave will decrease by a factor of (λ1 / 10m).
To determine what would happen to the frequency of the wave when the wavelength is increased while the speed remains constant, we can use the formula:
Speed = Wavelength x Frequency
Since the speed remains constant at 600 m/s, and the wavelength is increased to 10 m, we can rearrange the formula to solve for frequency:
Frequency = Speed / Wavelength
Plugging in the values, we have:
Frequency = 600 m/s / 10 m = 60 Hz
Therefore, when the wavelength of the wave is increased to 10 m while its speed remains at 600 m/s, the frequency of the wave would be 60 Hz.