Use the table of molar masses to complete the activity.
Element Molar Mass(g/mol)
Carbon 12.01
Hydrogen 1.01
Oxygen 16.00
A chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. In one to two sentences, make and justify a claim about the number of moles of ethanol the chemist will use.
CH3CH2OHg/mol=2*12.01+6*1.01+16=46.08g/mol
30/46.08=0.651mol.
So what is the justification or claim the chemist will use…The question is “A chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. In one to two sentences, make and justify a claim about the number of moles of ethanol the chemist will use?”. Do anyone know the correct answer? Please help!
The answer is :
The the chemist will use a number 0.65 moles of ethanol.
To determine the number of moles of ethanol used, divide the mass of ethanol (30 g) by its molar mass. The molar mass of ethanol can be calculated by adding the molar masses of carbon, hydrogen, and oxygen in its formula. Carbon has a molar mass of 12.01 g/mol, hydrogen has a molar mass of 1.01 g/mol, and oxygen has a molar mass of 16.00 g/mol. So, the molar mass of ethanol is 12.01 + (1.01 x 2) + 16.00 = 46.07 g/mol. Dividing 30 g by 46.07 g/mol gives us approximately 0.65 moles of ethanol. Therefore, the chemist will use approximately 0.65 moles of ethanol in their experiment.
molar mass C2H5OH = 2*12.01 + 6*1.01 + 1*16 = 46.08 g/mol
30 g C2H5OH x (1 mol/46.08 g) = ? moles C2H5OH.