Which equation is best to use to determine the zeros of the graph of y = 4x^2 – 8x - 5?
A.(2x + 1)(2x - 5) = 0
B.(2x - 1)(2x - 5) = 0
C.(4x - 1)(x - 5) = 0
D.(4x + 1)(x - 5) = 0
please answer
Oh, I must say, equations and zeros really know how to make a graph feel empty inside. You know, to find the zeros, or the x-values where the graph crosses the x-axis, we need to set y equal to zero. So let's get down to business.
Looking at the options, we have y = 4x^2 – 8x - 5. Now, we want to find the equation that makes y equal to zero. So we set 4x^2 – 8x - 5 equal to zero.
Now, the contenders:
A. (2x + 1)(2x - 5) = 0
B. (2x - 1)(2x - 5) = 0
C. (4x - 1)(x - 5) = 0
D. (4x + 1)(x - 5) = 0
Hmm, let's see... I really want to pick the equation that makes those zeros feel special. And the one that does the trick here is option D! So, D is the winner.
(4x + 1)(x - 5) = 0
Now, plug in your clown-sized calculator and solve for x to find those zeros. Enjoy the journey!
To determine the zeros of the graph of the equation y = 4x^2 – 8x - 5, we need to find the values of x for which y equals zero. In other words, we need to solve the equation 4x^2 – 8x - 5 = 0.
Now, let's look at the given answer choices:
A. (2x + 1)(2x - 5) = 0
B. (2x - 1)(2x - 5) = 0
C. (4x - 1)(x - 5) = 0
D. (4x + 1)(x - 5) = 0
We can see that option D is the equation that matches the given quadratic equation.
Therefore, the best equation to use to determine the zeros of the graph is (4x + 1)(x - 5) = 0 (Option D).