An object is dropped from a very tall building. What is the vertical distance in Meters that the object travels between the 6th and 7th second of travel? Hint: You are looking for the change in position related to time.
v(t) = g t
find velocities at six and seven seconds
find the average velocity ... [v(6) + v(7)] / 2
because it is a one second interval,
the average velocity is numerically equal to the distance