an elastic cord can be stretched zo its elastic limit by a load of 2N.if a 35cm length of the cord is extended 0.6cm by a force of 0.5N,what will be the length of the cord when the stretching force is 2.5N?
F = k x
0.5 = k * 0.6
k = 0.833 N/cm
F= 2.5 but it stops stretching after 2 N
2 = 0.833* x
x = 2.4 cm
L = 35 + 2.4 = 37.4 cm