four resistors of resistance 1ohm,2ohm,3ohm,4ohms are connect

ed in series and after,ward in parallel.calculate the net capacitance used in the system.in physics

Please check what you wrote.

looks like zero to me

Good point

Four resistors 1 ohm, 2 ohm 3 ohm, 4 ohm, 5 ohm are connected in and after series ward in parallel.calculate the combined resistance in each case

To calculate the net resistance of a system, we need to analyze the resistors that are connected both in series and parallel.

First, when the resistors are connected in series, their resistances add up. So, the total resistance in series is the sum of the individual resistances:

R_total = R1 + R2 + R3 + R4

Using the values given, we have:

R_total = 1Ω + 2Ω + 3Ω + 4Ω
= 10Ω

Next, when the resistors are connected in parallel, their reciprocals add up. So, the total resistance in parallel can be calculated using the formula:

1/R_total = 1/R1 + 1/R2 + 1/R3 + 1/R4

Substituting the values we have:

1/R_total = 1/1Ω + 1/2Ω + 1/3Ω + 1/4Ω

To find the reciprocal, we take the inverse (denominator becomes the numerator and vice versa), so:

1/R_total = 1/1Ω + 1/2Ω + 1/3Ω + 1/4Ω
= 1 + 1/2 + 1/3 + 1/4
= 4/4 + 2/4 + 3/4 + 4/4
= 13/4

Taking the reciprocal again:

R_total = 4/13 Ω

Therefore, the net resistance of the system, when the resistors are first connected in series and then in parallel, is 4/13 Ω.