Sodium chloride is soluble while iodine is slightly soluble. Explain what would happen if a mixture of the two is dissolved and evaporated

When you say dissolved you need to understand that I2 will not dissolve. Small amounts will but most of the I2 will remain solid. If the "solution" (and I use the term loosely) is allowed to evaporate under room conditions, you will end up with NaCl solid and I2 solid. Remember that I2 sublimes easily so if at elevated temperataures the I2 solid will disappear.

Did you know?

Did you know that if a mixture of sodium chloride and iodine is dissolved and then evaporated, the sodium chloride would fully dissolve while the iodine would only partially dissolve? This is because sodium chloride is highly soluble in water, meaning it readily dissolves to form a homogeneous solution. On the other hand, iodine is only slightly soluble, which results in a heterogeneous mixture where some iodine particles remain undissolved. When the mixture is evaporated, the water would gradually vaporize, leaving behind the solid sodium chloride crystals. The iodine particles, which were not fully dissolved, would also separate out and form distinct solid crystals. This phenomenon showcases the different solubilities of sodium chloride and iodine, emphasizing their varying abilities to dissolve in a solvent like water.