What is the length of the altitude drawn to the hypotenuse? The Figure is not to scale.

4, 16

To find the length of the altitude drawn to the hypotenuse, let's assume that the given side lengths are the legs of a right triangle.

Let's consider the triangle ABC, where AB and BC are the legs of the triangle and AC is the hypotenuse.

According to the given information, the lengths of the legs AB and BC are 4 units and 16 units respectively.

To find the length of the altitude drawn to the hypotenuse, we can use the geometric property that in a right triangle, the length of the altitude is given by the formula:

Length of altitude = (Length of one leg × Length of the other leg) / Length of the hypotenuse

Substituting the given values into the formula, we have:

Length of altitude = (4 × 16) / ? (as the length of the hypotenuse is not given)

Since the length of the hypotenuse is not provided, we cannot determine the exact length of the altitude drawn to the hypotenuse based on the given information.

To find the length of the altitude drawn to the hypotenuse of a right triangle, we can use the Pythagorean theorem.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

Given that the lengths of the two legs of the right triangle are 4 and 16 (not to scale), let's label them as leg A and leg B, respectively.

Let's assume that the altitude drawn to the hypotenuse is the missing side, and we'll label it as altitude C.

Using the Pythagorean theorem, we have the equation:

A^2 + C^2 = B^2

Plugging in the values we have:

4^2 + C^2 = 16^2

16 + C^2 = 256

C^2 = 256 - 16

C^2 = 240

Taking the square root of both sides, we find that:

C = √240

Hence, the length of the altitude drawn to the hypotenuse is √240 units.

In a right triangle, if the legs are a and b, the hypotenuse is c, and the altitude to the hypotenuse is h, then using similar triangles,

a/h = h/H
h^2 = aH
so plug in your numbers. If the two you gave are the legs, then
h^2 = 4*4√17
h = 4∜17