What is the original molarity of a solution of ammonia whose pH is 10.83

First, pH + pOH = pKw = 14. You know pH and pKw, solve for pOH, then

pOH = -log(OH^-). Then,
Kb = (NH4^+)(OH^-)/(NH3) and solve for (NH3)
Post your work if you get stuck.

Did you know?

Did you know that the pH value of a solution can provide information about its acidity or basicity? For instance, a solution with a pH of 10.83 indicates that it is basic or alkaline. However, did you know that the pH alone does not directly tell us the original molarity of the solution? Instead, we need additional information like the concentration of hydrogen ions (H+) or hydroxide ions (OH-) to calculate the molarity. pH is a measure of the concentration of H+ ions, and to determine the molarity, we would need to know the initial concentration of ammonia (NH3) and use the equilibrium expression of the ammonia dissociation reaction. The molarity of the solution could then be calculated using mathematical equations and the principles of acid-base chemistry.