Bob rolls two number cubes with sides labeled 1-6. What is the probability of rolling the sum of 9?
Can roll 6&3, 3&6, 4&5, 5&4 out of 36 possibilities.
To find the probability of rolling the sum of 9 with two number cubes, we need to determine the number of favorable outcomes (rolling a sum of 9) and the total number of possible outcomes.
Let's first determine the total number of possible outcomes when rolling two number cubes. Since each cube has 6 sides labeled 1-6, there are a total of 6 possible outcomes on the first cube and 6 possible outcomes on the second cube. Thus, the total number of possible outcomes is 6 x 6 = 36.
Next, let's determine the number of favorable outcomes, which is the number of ways we can roll a sum of 9. The following combinations yield a sum of 9: (3,6), (4,5), (5,4), and (6,3). Therefore, there are 4 favorable outcomes.
Finally, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes. So, the probability of rolling a sum of 9 is 4/36, which simplifies to 1/9.
Therefore, the probability of rolling the sum of 9 with two number cubes is 1/9.
To find the probability of rolling the sum of 9 when rolling two number cubes, we need to determine the number of favorable outcomes and the total number of possible outcomes.
To calculate the favorable outcomes, we need to list all the combinations of numbers that sum up to 9:
- (3, 6)
- (4, 5)
- (5, 4)
- (6, 3)
So, there are four favorable outcomes.
Next, we need to determine the total number of possible outcomes when rolling two number cubes. Since each number cube has six sides, the total number of outcomes for each cube is 6. Since we are rolling two cubes, we multiply the number of outcomes for each cube together: 6 x 6 = 36.
Therefore, the probability of rolling the sum of 9 is the favorable outcomes divided by the total number of outcomes: 4/36.
Simplifying this fraction, we get 1/9.
Hence, the probability of rolling the sum of 9 is 1/9.