find the standard form of the equation of the circle with a center at (6, -3) and a point on the circle at (-2,4)
(x-h)^2 + (y-k)^2=t^2
ok so using the distance between points i got
thank you
(x-6)^2+(y+3)^2=117
(x-h)^2 + (y-k)^2=t^2
ok so using the distance between points i got
thank you
(x-6)^2+(y+3)^2=117