Sulfur dioxide and nitrogen dioxide react at 298 K via the reaction
SO2(g)+NO2(g)⇌SO3(g)+NO(g)
A system at equilibrium contains 0.370 mol SO2 , 0.370 mol NO2 , 0.804 mol SO3 , and 0.588 mol NO. O2 is added to the container and NO reacts completely with the O2. Calculate the amount of SO3 in the container after the system returns to equilibrium.
mass SO3 : (in g)
I'm confused. How much O2 is added?
To calculate the amount of SO3 in the container after the system returns to equilibrium, we need to consider the stoichiometry of the reaction and use the given amounts of reactants to determine the amount of SO3 produced.
First, we need to determine the limiting reactant, which is the reactant that will be completely consumed and will determine the maximum amount of product that can be formed. In this case, NO is reacting completely with O2 to form NO2, so NO is the limiting reactant.
To calculate the amount of SO3 produced, we can use the balanced equation and the stoichiometry of the reaction. Looking at the balanced equation:
SO2(g) + NO2(g) ⇌ SO3(g) + NO(g)
We can see that the stoichiometry is 1:1 for SO2 to SO3. Therefore, the amount of SO3 formed will be equal to the amount of SO2 reacted.
Given that the system at equilibrium contains 0.370 mol SO2 and 0.804 mol SO3, and we know that the equilibrium concentrations of the reactants and products remain constant, we can calculate the amount of SO3 in the container after the system returns to equilibrium.
Since the amount of SO2 reacted is equal to the amount of SO3 formed, we can use the initial amount of SO2 (0.370 mol) as the amount of SO3 present in the container after the system returns to equilibrium.
Therefore, the amount of SO3 in the container after the system returns to equilibrium is 0.370 mol.
To convert this amount to mass (in grams), we need to use the molar mass of SO3, which is 80.06 g/mol.
Mass of SO3 = moles of SO3 * molar mass of SO3
= 0.370 mol * 80.06 g/mol
= 29.647 g
Therefore, the mass of SO3 in the container after the system returns to equilibrium is 29.647 grams.