When a boy is sitting 1 meter from the center of a see-saw, another boy must sit on the
opposite side 0.5 meter farther from the center compared to the first boy to maintain
balance. When the first boy carries an additional weight of 10 kg and sits 1.5 meters from
the center, the second boy must now move to 3 meters from the center to maintain
balance. Determine the weight of the two boys.
weight of boy ---- x , distance from centre = 1 m
weight of other boy ---- y , distance from centre = 1.5 m
1x = 1.5y ---> x = 1.5y
1.5(x+10) = 3y
1.5(1.5y+10) = 3y
2.25y + 15 = 3y
.75y = 15
y = 20
then x = 1.5y = 30
State you conclusion